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Smith committed to “Not Get Out To” Yasir Shah after 7-finger celebration


Australian batsman Steve Smith has been dismissed by Pakistan spinner Yasir Shah repeatedly playing against Pakistan. Going down the field against Pakistan means that Smith will fall victim to Yasir Shah.

Smith committed to "Not Get Out To" Yasir Shah after 7-finger celebration

Smith, who has been the victim of Shah in the last 7 innings against the Asian team, has vowed not to repeat the incident in the second Test of the series against Pakistan in Adelaide from Friday, November 29.

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Smith was bowled out by Yasir only after scoring only 4 runs in the first Test in Brisbane. The Pakistani spinner then raised his finger and celebrated with seven fingers. Which meant he dismissed the world best batsman 7 times.

“I have been a victim to him repeatedly,” Smith told reporters today.

“That seems unusual now. This has helped me to be more committed to not get out by him [Yasir Shah] in the next match. I’ll be more disciplined when batting against him.”

The 30-year old star, however, had been unaware of Yasir’s success against him. “He has taken my wicket several times,” Smith said.

“I was out for a low run and that is how the discussion started. I have been out twice in the second innings but have had some fun shots. So I’m not too worried. Yasir has really bowled well in Gabba. The spinners didn’t have much to do there but did well. See you in Adelaide this time.”

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